# Graph Traversals - Depth First Search Algorithm

#### In this chapter

A very common and natural way to traverse a graph, directed or undirected, is analogous to a pre-order traversal of a binary tree and it is called a depth-first search, or DFS for short. DFS is a backtrack-style traversal that visits a node and then recursively visits all nodes adjacent to it that have not yet been visited. To prevent the algorithm from going into an endless loop by revisiting nodes, when a node is visited for the first time it is marked.

Here’s an animation showing Depth-first search. ## DFS Algorithm

DFS is typically implemented using a Stack to store the vertices. Let’s start by looking at some simple pseudo code.

DFS(s):
put s into the stack
while the stack is not empty
take v from the bag
if v is unmarked
mark v
for each edge vw
put w into the stack


Depth-first search will marks every node reachable from s and nothing else. The algorithm clearly marks each vertex in G at most once.

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### Depth First Search

Here’s a little more concrete, yet still general algorithm that does nothing other than traverse the graph is:


for all vertices v in V { // mark all vertices as unvisited
v.visited = false;
}

void Graph::DFS( Vertex v) {
v.visited = true;
for each vertex w that is adjacent to v {
if ( !w.visited) {
DFS(w);
}
}
}


If an undirected graph is not connected, this will not visit every node. Similarly, if a directed graph is not strongly connected, it will not visit every node. The solution is to use a numbering scheme. Initially every vertex will have its number set to 0 . When it is visited by DFS, it will get a non-zero number. If after processing all vertices, some still have zero as their number, they were not visited and must be in a part of the graph that was not connected to where the DFS started. DFS can be called for each vertex whose number is zero. The following C++ algorithm illustrates this idea and also introduces the concept of tree edges and back edges.

void Graph::DFS(Vertex v, Vertex u) {
// u is the parent of v in the search , i.e., (u , v) is the edge
i += 1;
v.number = i;
for all w adjacent to v {
if (w.number == 0) {
// this is a tree edge
Tree_edges = Tree_edges + (v, w);
DFS(w, v);
} else if (w.number < v.number && w != u) {
// this is a back edge
Back_edges = Back_edges + (v, w);
}
}
}
// Assume that 0 represents a non - existent node i.e., all nodes have labels greater than 0
void Graph::DFS() {
i = 0;
Tree_edge = {};
Back_edges = {};
for all v in V {
v.number = 0;
}
for all v in V {
if (v.number == 0) {
DFS(v, 0);
}
}
}

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## DFS Complexity or Performance Analysis

If we build DFS using a stack, that supports insertions (push) and deletions (pop) in O(1) time each, the algorithm runs in O(V + E) time. The for loop (†) is executed exactly once for each marked vertex, and therefore at most V times. Each edge uv is put into the stack exactly twice; once as the pair (u, v) and once as the pair (v, u), so it is executed 2E times. This assumes that the graph is represented using adjacency lists.